-5a^2-19a+0=0

Solution for -5a^2-19a+0=0 equation:

-5a^2-19a+0=0

We add all the numbers together, and all the variables

-5a^2-19a=0

a = -5; b = -19; c = 0;
Δ = b2-4ac
Δ = -192-4·(-5)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-19}{2*-5}=\frac{0}{-10}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+19}{2*-5}=\frac{38}{-10}
=-3+4/5
$